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Byju's Answer

Standard VIII

Chemistry

Ways to Define Concentration

0.1 millimole...

Question

$0.1$ millimole of $C d {S O}_{4}$ are present in $10$ mL acid solution of $0.08$ N $H C l$ . Now $H_{2} S$ is passed to precipitate all the ${C d}^{2 +}$ ions. The pH of the solution after filtering off precipitate, boiling of $H_{2} S$ and making the solution $100$ mL by adding $H_{2} O$ will be:

2

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Solution

The correct option is A $2$

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Similar questions

Q. 0.1 milli moles of

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H_{2} S

is passed to precipitate all the

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H_{2} S

and making the solution 100 ml by adding

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0.1

milli mole of

C d {S O}_{4}

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0.08 N

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H_{2} S

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0.1 millimole of CdSO4 are present in 10 mL acid solution of 0.08 N HCl. Now H2S is passed to precipitate all the Cd2+ ions. The pH of the solution after filtering off precipitate, boiling of H2S and making the solution 100 mL by adding H2O will be:

The correct option is A 2

$0.1$ millimole of $C d {S O}_{4}$ are present in $10$ mL acid solution of $0.08$ N $H C l$ . Now $H_{2} S$ is passed to precipitate all the ${C d}^{2 +}$ ions. The pH of the solution after filtering off precipitate, boiling of $H_{2} S$ and making the solution $100$ mL by adding $H_{2} O$ will be:

The correct option is A $2$