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Question

0.1 mol of ethane gas (C2H6) and 0.3 moles of oxygen gas are sealed in a flask at 27 oC and 1.0 atm pressure. The flask is heated to 1000 K and only the following reaction takes place:
C2H6+52 O22CO+3H2O

Calculate the partial pressure of the products of the reaction in the reaction mixture.

A
4.58 atm
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B
4.17 atm
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C
2.08 atm
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D
0.27 atm
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Solution

The correct option is B 4.17 atm
1 mole of ethane needs 2.5 moles of oxygen, hence 0.1 moles will need 0.25 moles. Hence the limiting reagent is ethane. The final composition of the products at 1000 K is given by:
C2H6=0 molO2=0.05 molCO=0.20 molH2O=0.30 mol
Total=0.55 mol
P1V=n1RT1P2V=n2RT2P2=n2T2n1T1×P1=0.55×10000.4×300×1=5512 atm

Total moles of products = 0.50 mol
(0.05 moles oxygen which is a reactant).

Partial pressure of gaseous products =0.50.55×5512=4.17 atm

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