Question

0.1 moles of a diatomic gas at ${27}^{0}C$ is heated at constant pressure, so that the volume is doubled. If $R=2$ cal/mol, the work done is :

• A. 150 cal
• B. 60 cal
• C. 40 cal
• D. 30 cal

Answer 1

The correct option is B 60 cal

The initial temperature for the process is 300 K.

Now, following Charles' Law, where for a constant pressure, if volume is doubled, even the temperature will get doubled.

New temperature is 600 K.

The work done for the process will be,

W = $nR\delta T$

W = $0.1\times 2\times (600-300)$

W = 60 cal

Option B is correct.