You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XIII

Chemistry

Types of Redox Reactions

0.1 N K2C2O4....

Question

$0.1 N K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} .4 H_{2} O$ solution reacts completely with $20 ml of 0.05 M$ $K M n O_{4}$ solution in acidic medium. Another sample of the same solution of $K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} .4 H_{2} O$ having the same volume is titrated with $\frac{1}{8} M N a O H$ solution. Then, the volume of $N a O H$ solution (in ml) required for titration is:

Open in App

Solution

Redox titration
$Eq. of K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} . 4 H_{2} O = Eq. of K M n O_{4}$
$\frac{0.1 \times V}{1000} = \frac{20 \times 0.05 \times 5}{1000}$
$V = 50 ml$
$n$ factor of $K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} .4 H_{2} O$
For redox titration $= 8$
For acid base titration $= 6$
$∴$ for acid base titration normality of
$K_{2} C_{2} O_{4} .3 H_{2} C_{2} O_{4} .4 H_{2} O = \frac{0.1}{8} \times 6 N$
Eq. of acid = Eq. of base
$\frac{0.1 \times 50}{8 \times 1000} \times 6 = \frac{1}{8} \times \frac{V ml}{1000}$
$V ml = 30 ml$

Suggest Corrections

Similar questions

Q. 50 ml of

H_{2} O_{2}

solution when titrated with 0.1 M

K M n O_{4}

solution in acidic medium, volume required is 40 ml. Volume strength of

H_{2} O_{2}

solution is

Q. A

8 g m

sample of iron are containing

V %

(by wt) of iron

F e^{2 +}

was present in

1 L

solution. This solution required

V m L

of a

K M n O_{4}

solution for oxidation of

F e^{2 +}

in acidic medium. If in another titration

20 m L

of same

K M n O_{4}

is required, for oxidation of

20 m L H_{2} O_{2}

in acidic medium. Find volume strength of

H_{2} O_{2}

Q. A

100 m L

solution of

0.1 N H C l

was titrated with

0.2 N N a O H

solution. The titration was discontinued after adding

30 m L

N a O H

solution. The titration was completed by adding

0.25 N K O H

solution. The volume of

K O H

required for completing the titration is:

Q. 100 mL solution of 0.1 M

H C l

was titrated with 0.2

N a O H

solution. The titration was discontinued after the addition of 30 mL of

N a O H

. The remaining titration was completed with the addition of 0.5 M

K O H

. The volume of

K O H

required for completing the titration is:

A 100ml solution of 0.1N HCl was titrated with 0.2N NaOH solution . The titration was discontinued after adding 30ml of NaOH solution . The remaining titration was completed by adding 0.25 N KOH solution . The volume of KOH required for completing the titration is ___ .

(a) 70 ml. (b) 32 ml. (c)35 ml. (d)16ml

Join BYJU'S Learning Program

0.1 N K2C2O4.3H2C2O4.4H2O solution reacts completely with 20 ml of 0.05 M KMnO4 solution in acidic medium. Another sample of the same solution of K2C2O4.3H2C2O4.4H2O having the same volume is titrated with 18 M NaOH solution. Then, the volume of NaOH solution (in ml) required for titration is: