Question

0.10 g of organic compound containing phosphorous gave 0.222g of $M{g}_2{P}_2{O}_7$. Then, the % of P is

• A. 62
• B. 6.2
• C. 31
• D. 13

Answer 1

The correct option is A 62

$\%P=\frac{62\times \text{mass of magnesium pyrophosphate}\times 100}{222\times \text{mass of compound}}=\frac{62\times 0.222\times 100}{222\times 0.10}=62$