0.12 kg of copper of specific heat capacity hundred cal kg c . And at 20 degree celsius is heated by burner for 2 minutes which supplies heat @ rate of 20 calories per second calculate the final temperature of copper

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Solution

$H e a t a d d e d = S p e c i f i c h e a t \times m a s s \times C h a n g e i n t e m p e r a t u r e H e a t a d d e d = 20 c a l / s e c F o r 2 m i n u t e s h e a t a d d e d = \frac{20}{1} \times 2 \times 60 = 2400 C a l T_{1} = 20 d e g r e e T_{2} = ? S p e c i f i c h e a t = 100 c a l / K g / C M a s s = 0.12 K g S u b s t i t u t e a l l t h e s e v a l u e 2400 = 100 \times 0.12 \times (T_{2} - 20) T_{2} - 20 = \frac{2400}{100 \times 0.12} = 200 T_{2} = 200 + 20 = 220 d e g r e e C$

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