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Balanced Chemical Equation

0.1225 g of p...

Question

0.1225 g of potassium chlorate decomposes completely. Write the possible chemical equation and the amount of oxygen liberated.

4 K C l O_{3} \to 4 K C l + 6 O_{2}, 0.048 g

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4 K C l O_{3} \to 4 K C l + 5 O_{2}, 0.048 g

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2 K C l O_{3} \to 2 K C l + 3 O_{2}, 0.048 g

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2 K C l O_{3} \to 2 K C l + 3 O_{2}, 0.48 g

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Solution

The correct option is A $2 K C l O_{3} \to 2 K C l + 3 O_{2}, 0.048 g$
The balanced equation for the reaction is:
$2 K C l O_{3} \to 2 K C l + 3 O_{2}$
$122.5 \times 2 g$ of $K C l O_{3}$ produces $= 32 \times 3 g$ of $O_{2}$
$0.1225 g$ of $K C l O_{3}$ produces $= \frac{32 \times 3 \times 0.1225}{122.5 \times 2} = 0.048 g$ of $O_{2}$
Therefore $(C)$ is the correct answer.

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