0-1253-0-252-0-52-0-57-

The correct option is D 0Here, (0.125)^3 ÷ (0.25)^2 × (0.5)^2 = (0.5)^7 ? ⇒{(0.5)63}63 + (0.5)^2 × 2× (0.5)^2 = (0.5)^7 ? ⇒{(0.5)^3}^3 + (0.5)^2 × 2× (0.5)^2 = ...

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Byju's Answer

Standard IX

Mathematics

Quotient Law

0.1253÷0.252×...

Question

$(0.125)^{3} \div (0.25)^{2} \times (0.5)^{2} = (0.5)^{7 - ?}$

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Solution

$H e r e, (0.125)^{3} \div (0.25)^{2} \times (0.5)^{2} = (0.5)^{7 - ?}$
$\Rightarrow {(0.5) 63} 63 + (0.5)^{2 \times 2} \times (0.5)^{2} = (0.5)^{7 - ?} \Rightarrow {(0.5)^{3}}^{3} + (0.5)^{2 \times 2} \times (0.5)^{2} = (0.5)^{7 - ?} \Rightarrow {(0.5)}^{9} + (0.5)^{4} \times (0.5)^{2} = (0.5)^{7 - ?} \Rightarrow (0.5)^{9 - 4} \times (0.5)^{2} = (0.5)^{7 - ?} \Rightarrow (0.5)^{7} = (0.5)^{7 - ?} \Rightarrow 7 - ? = 7 ? = 0$

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(0.125)3÷(0.25)2×(0.5)2=(0.5)7−?

Here,(0.125)3÷(0.25)2×(0.5)2=(0.5)7−? ⇒{(0.5)63}63+(0.5)2×2×(0.5)2=(0.5)7−?⇒{(0.5)3}3+(0.5)2×2×(0.5)2=(0.5)7−?⇒{(0.5)}9+(0.5)4×(0.5)2=(0.5)7−?⇒(0.5)9−4×(0.5)2=(0.5)7−?⇒(0.5)7=(0.5)7−?⇒7−?=7?=0

$(0.125)^{3} \div (0.25)^{2} \times (0.5)^{2} = (0.5)^{7 - ?}$