$0.126 g$ of an acid requires $20 m L$ of $0.1 N N a O H$ for complete neutralization. Equivalent weight of the acid is:

45

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53

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40

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63

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Solution

The correct option is D $63$
Weight of acid = 0.126 g

Volume = 20 ml

For neutralization, 20 ml of acid requires 0.1N acid.

Normality of acid = 0.1N

$E q u i v a l e n t w e i g h t = \frac{W e i g h t o f a c i d}{N o r m a l i t y \times v o l u m e}$

$= \frac{0.126 \times 1 \times 1000}{20 \times 0.1}$

$= 63 g / e q$

Therefore, the equivalent weight of acid is 63.

Hence, option D is correct.

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0.126 g of an acid requires 20 mL of 0.1 N NaOH for complete neutralization. Equivalent weight of the acid is:

The correct option is D 63Weight of acid = 0.126 gVolume = 20 mlFor neutralization, 20 ml of acid requires 0.1N acid.Normality of acid = 0.1N Equivalent weight=Weight of acidNormality×volume =0.126×1×100020×0.1 =63g/eqTherefore, the equivalent weight of acid is 63.Hence, option D is correct.

$0.126 g$ of an acid requires $20 m L$ of $0.1 N N a O H$ for complete neutralization. Equivalent weight of the acid is: