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Ion Electron Method

0.126 gm of H...

Question

0.126 gm of $H_{2} C_{2} O_{4} .2 H_{2} O$ is completely oxidized by ‘y’ ml of 0.01N $K M n O_{4}$ solution in acidic medium. The value of ‘y’ is

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200

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2000

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Solution

The correct option is B
200

$N o . o f m o l e s o f H_{2} C_{2} O_{4} .2 H_{2} O = N o . o f m o l e s o f K M n O_{4}$
$\frac{0.126}{63} = \frac{0.1 \times y}{1000}$
$y = \frac{126}{63 \times 0.01} = 200 m l$

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