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Question

0.12mL of a solution of KOH (59% by mass KOH) specific gravity 1.5g/cm3 is diluted to 250mL. Calculate the value of (12pH of solution) (nearest integer).

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Solution

First calculate the hydroxide ion concentration.
[OH]=0.12mL×1.5g1mL×59100×1000mL1L56.1g1mol×250mL=7.57×103M
Now calculate the pOH of solution.
pOH=log[OH]=log7.57×103=2.20.
Now calculate the pH of the solution pH=142.20=11.80.
Hence, the pH of the solution is 11.80.
Answer =1211.80=.200

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