Question

$0.132$ g of an organic compound gives $50$ mL of $N_2$ at STP. The weight percentage of nitrogen in the compound is :

• A. $15$
• B. $20$
• C. $48.9$
• D. $47.34$

Answer 1

The correct option is D $47.34$

Since, 22.4 L corresponds to 1 mole of a gas at STP,

$22.4$ L of $N_2\equiv$ $28$ g

$50$ mL of $N_2\equiv$ $0.0625$ g

% of $N=\frac{0.0625}{0.132}\times 100=$ $47.34$ %

Hence, option D is correct.