Question

$0.14$ g of an acid required $12.5$ mI of $0.1$ N $NaOH$ for complete neutralisation. The equivalent mass of the acid is :

• A. $63$
• B. $56$
• C. $45$
• D. $112$

Answer 1

The correct option is D $112$

mEq. of NaOH $=12.5\times 0.1=1.25$
mEq. of acid = mEq.of NaOH
$Equivalent=\frac{Weight}{Ew}$
$\therefore Ew=\frac{Weight}{Equivalent}=\frac{0.14}{1.25\times {10}^{-3}}=112$