0.15 g of a substance dissolved in 15 g of a solvent is boiled at a temperature higher by 0.216∘ C than that of the pure solvent. Find out the molecular weight of the substance (Kf for solvent is 2.16 K kg m−1)
A
1.01
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B
10.1
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C
100
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D
1000
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Solution
The correct option is C100 Amount of solute (wA)=0.15 g
Amount of solvent (wB)=15 g
The change in temperature is 0.216∘ C or 0.216 K. Kf=2.16 K kg m−1
The change in temperature is ΔT=1000×Kf×wAwB×mA⇒0.216=1000×2.16×0.1515×mA⇒mA=100