CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

0.15 g of a substance dissolved in 15 g of a solvent is boiled at a temperature higher by 0.216 C than that of the pure solvent. Find out the molecular weight of the substance (Kf for solvent is 2.16 K kg m1)

A
1.01
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10.1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
100
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1000
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 100
Amount of solute (wA)=0.15 g
Amount of solvent (wB)=15 g
The change in temperature is 0.216 C or 0.216 K.
Kf=2.16 K kg m1
The change in temperature is ΔT=1000×Kf×wAwB×mA0.216=1000×2.16×0.1515×mAmA=100

flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Atomic Mass
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon