$0.156 g m$ of an organic compound on heating with fuming $H N O_{3}$ , and $A g N O_{3}$ , gives $0.235 g m$ of $A g l$ . Calculate the percentage of iodine in the compound.

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Solution

Mass of organic compound, $W = 0.156 g m$
Mass of $A g I$ , $W_{1} = 0.235 g m$
$A g I 235 g m \equiv I 127 g m$
Percentage of Iodine = $\frac{127}{235} \times \frac{W_{1}}{W} \times 100$
$= \frac{127}{235} \times 0.235 0.156 \times 100 = 81.41$ [ $4 A n s w e r$ ]

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0.156gm of an organic compound on heating with fuming HNO3, and AgNO3, gives 0.235gm of Agl. Calculate the percentage of iodine in the compound.

Mass of organic compound, W=0.156gmMass of AgI, W1=0.235gm AgI235gm≡I127gmPercentage of Iodine = 127235×W1W×100=127235×0.2350.156×100=81.41 [4Answer]

$0.156 g m$ of an organic compound on heating with fuming $H N O_{3}$ , and $A g N O_{3}$ , gives $0.235 g m$ of $A g l$ . Calculate the percentage of iodine in the compound.

Mass of organic compound, $W = 0.156 g m$
Mass of $A g I$ , $W_{1} = 0.235 g m$
$A g I 235 g m \equiv I 127 g m$
Percentage of Iodine = $\frac{127}{235} \times \frac{W_{1}}{W} \times 100$
$= \frac{127}{235} \times 0.235 0.156 \times 100 = 81.41$ [ $4 A n s w e r$ ]