0.18g of Al reacts with dil.HCl to give H2. The volume of H2 evolved at STP is: (Atomic weight of Al=27)
A
1.12 litre
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B
0.224 litre
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C
3.33 litre
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D
4.44 litre
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Solution
The correct option is B 0.224 litre 2Al(s)+6HCl(aq)→2AlCl3(s)+3H2(g) At STP, 2 mol of aluminium i.e. (2×27g) of Al will produce (3×22.4)L of H2 0.18g of Al will produce (3×22.42×27×0.18)=0.224L of H2