Question

0.183 of organic monobasic acid required 15 ml of decinormal sodium hydroxide for complete neutralization. Calculate the molecular Mass of the Acid.

• A. 142
• B. 124
• C. 122
• D. 130

Answer 1

The correct option is C 122

Mass of organic Acid = 0.183 g
Volume of 0.1 N NaOH solution = 15 ml
Equivalent Mass of Acid $=\frac{W\times 1000}{N_1{V}_1}$
$=\frac{0.183\times 1000}{0.1\times 15}=122$
Molecular Mass of Acid = n $\times$ Equivalent Mass
$=1\times 122=122$ [$\because$ n=1 (Basicity)]