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Types of Redox Reactions

0.1M of HA ...

Question

0.1M of $H A$ is titrated with $0.1 M$ $N a O H$ , calculate $p H$ at end point.
Given $K (H A) =$ $5 \times 10^{- 6}$ and $α ≪ 1$

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Solution

Given $p K_{a} = + 5.3010 (K_{a} = 5 \times 10^{- 6})$
Since at the end point,
Molarity of salt= $\frac{0.1}{2} M = 0.05 M = C$
$p H$ of salt of weak acid & strong base
$p H = \frac{p K_{w} + p K_{a} + log C}{2}$
$= \frac{1}{2} [14 + 5.3010 + (- 1.3010)]$
$\Rightarrow p H = 9$

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