Question

$0.2$ litres of ammonia at ${27}^{o}C$ and $2$ atm pressure is neutralized by $160$ ml of sulphuric acid. Find the normality of sulphuric acid.

• A. $0.01N$
• B. $0.2N$
• C. $2N$
• D. $0.1N$

Answer 1

The correct option is D $0.1N$

For ammonia:

$PV=nRT$

$P=2atm,V=0.2litres,T=273+27=300K,R=0.0821Latm{K}^{-1}mo{l}^{-1}$

$0\cdot 2\times 2=n\times 0\cdot 821\times 300$

$n=\frac{0\cdot 4}{0\cdot 0821\times 300}$

$=0\cdot 0162$

$N_1{V}_1=N_2{V}_2$

Ammonia has a capacity to take a single $H^{+}$ ion and therefore, the equivalents of ammonia is equal to its moles.

$\frac{0\cdot 0162}{V_1}\times V_1=N_2\times 0\cdot 160$

$N_2=\frac{0\cdot 0162}{0\cdot 160}N$

$N_2=0\cdot 1N$