wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

0.2 mole of HCl and 0.1 mole of barium chloride were dissolved in water to produce a 500 mL solution. The molarity of the Cl ions is:

A
0.80 M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.09 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.06 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.12 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.80 M
Number of moles of HCl dissolved (nHCl)=0.2 mol

And number of moles of Cl obtained from HCl,

Ncl=nHCl=0.2 mol

Number of moles of BaCl2 dissolved
(nBaCl2)=0.1 mol

And number of moles of Cl obtained from BaCl2,

ncl=2(nBaCl2)=2×0.1=0.2 mol

Thus, total number of moles of Cl dissolved
=0.2+0.2=0.4 mol

Now molarity=no.of molesVolume(in mL)×1000

=0.4500×1000=0.80 M

Thus, molarity of Cl ion is 0.80 M.

So, option (D) is the correct answer.

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon