You visited us 1 times! Enjoying our articles? Unlock Full Access!

Elevation in Boiling Point

0.2 mole of H...

Question

0.2 mole of HCl and 0.1 mole of CaCl2 were dissolved in water to have 500 ml of solution , the molarity of Cl- (minus) ions is__.

1: 0.04M

2: 0.8M

3: 0.4M

4: 0.08M

Open in App

Solution

The dissociation reactions are
HCl ⇔ H+ + Cl- and CaCl2 ⇔ Ca2+ + 2Cl-

Moles of Cl- formed from 0.2 moles of HCl = 0.2 moles
Moles of Cl- formed from 0.1 moles of CaCl2 = 2 X 0.1 = 0.2 moles
Total moles of Cl- = 0.4mol
Volume of solution = 500ml = 0.5L
Molarity of Cl- = moles Cl-/Volume of solution = 0.4/0.5 = 0.8M

Suggest Corrections

Similar questions

0.2 mole of HCl and 0.1 mole of CaCl₂ were dissolved in water to have 500 ml of solution, the molarity of Cl^- ions is

(1)0.04 M (2)0.8 M (3)0.4 M (4)0.08 M

CaC l_{2}

C l^{-}

0.2

H C l

0.2

500 m l

C l^{-}

0.4 m o l e s

0.2 m o l e s

C a C l_{2}

500 m L

C l^{-}

C l^{-}

0.2

H C l

0.1

C a C l_{2}

Join BYJU'S Learning Program