Question

$0.20$g of a hydrocarbon on combustion gave $0.66$g of $C{O}_2$. The percentage of hydrogen in the hydrocarbon is about:

• A. $35$%
• B. $47$%
• C. $10$%
• D. $25$%

Answer 1

The correct option is C $10$%

$\%$ of C$=\frac{12}{44}\times \frac{WeightofC{O}_2}{Weightofcompound}\times 100$

$=\frac{12}{44}\times \frac{0.66}{0.20}\times 100=90\%$

Thus, $\%$ of $H=100-\%$ of C

$=100-90=10\%$.