0.216g of an organic compound gave $28.8 c m ^{3}$ of moist nitrogen measured at 288k and 732.7 mm pressure. The percentage of $N_{} 2$ in the substance is approximately (aqueous tension is 12.7mm)

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Solution

The correct option is A
15

Volume of $N_{2}$ at NTP= $\frac{28.8 (732.7 - 127)}{288} \times \frac{273}{760}$

= 25.86 cc

$%$ of $N_{2} = \frac{28}{22, 400} \times \frac{25.86}{0.216} \times 100 = 14.96 \approx 15.$

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0.216g of an organic compound gave 28.8cm­3 of moist nitrogen measured at 288k and 732.7 mm pressure. The percentage of N­2 in the substance is approximately (aqueous tension is 12.7mm)

The correct option is A 15 Volume of N2 at NTP= 28.8(732.7 − 127)288 × 273760 = 25.86 cc % of N2 = 2822,400 × 25.860.216 × 100 = 14.96 ≈ 15.

0.216g of an organic compound gave $28.8 c m ^{3}$ of moist nitrogen measured at 288k and 732.7 mm pressure. The percentage of $N_{} 2$ in the substance is approximately (aqueous tension is 12.7mm)

The correct option is A
15

Volume of $N_{2}$ at NTP= $\frac{28.8 (732.7 - 127)}{288} \times \frac{273}{760}$

= 25.86 cc

$%$ of $N_{2} = \frac{28}{22, 400} \times \frac{25.86}{0.216} \times 100 = 14.96 \approx 15.$