$0.24$ g of a volatile liquid upon vaporisation gives $45$ ml of vapours at STP. What will be the vapour density of the substance? (Density of $H_{2} = 0.089 g L^{- 1}$ )

9.539

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59.73

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5.993

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95.39

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Solution

The correct option is B $59.73$
It is an example of Victor Meyer's method.
$M W = \frac{M a s s o f c o m p o u n d \times 22400}{V o l u m e o f v a p o u r s a t S T P}$
$= \frac{0.24 \times 22400}{45} = 119.46$
Vapour density $= \frac{M W}{2} = 119.46 2 = 59.7$

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