Question

$0.24g$ of an organic compound gave $0.22g$ $C{O}_2$ on complete combustion. If it contains $1.66\%$ hydrogen, then the percentage of $C$ and $O$ will be:

• A. $12.5$ and $36.6$
• B. $25$ and $75$
• C. $25$ and $36.6$
• D. $25$ and $58.4$

Answer 1

Answer: (B)

$25$ and $75$

$\%$ of $C=\frac{12}{44}\times \frac{MassofC{O}_2}{Massofsubstance}\times 100$

$=\frac{12\times 0.22}{44\times 0.24}\times 100=25$

$C\%=25,H\%=1.66$

Total $O\%=100-(25+1.66)=73.4$