You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Colour

0.248 g of an...

Question

0.248 g of an organic compound was heated in carious tube with conc. ${H N O}_{3}$ . Produced $H_{3} {P O}_{4}$ was precipitated as $M g ({N H}_{4}) {P O}_{4}$ , which formed 0.444 g ${M g}_{2} P_{2} O_{7}$ on ignition. What percentage of $^{'} P^{'}$ is present in compound?
$(M g = 24, P = 31)$

50%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

82%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 50%
Moles of $M g_{2} P_{2} O_{7} = \frac{0.444}{222} = 2 \times 10^{- 3}$ $m o l e s$
Mass of $P$ in $M g_{2} P_{2} O_{7} = 2 \times 10^{- 3} \times 62 = 124 \times 10^{- 3}$
$% P i n o r g a n i c c o m p o u n d = \frac{M a s s o f P}{M a s s o f o r g a n i c c o m p o u n d} \times 100$
$= \frac{124 \times 10^{- 3}}{0.248} \times 100 = 50 %$

Suggest Corrections

Similar questions

Q. 0.248 g of an organic compound was heated in carius tube with conc.

H N O_{3}

. Produced

H_{3} P O_{4}

was precipitated as

M g (N H_{4}) P O_{4}

, which formed 0.444 g

M g_{2} P_{2} O_{7}

on ignition What percentage of 'P' is present in compound? (Mg = 24, P = 31)

0.5 g m

of an organic substance containing phosphorous was heated with conc.

H {N O}_{3}

in the Carius tube. The phosphoric acid thus formed was precipitated with magnesia mixture

(M g {N H}_{4} {P O}_{4})

which on ignition gave a residue of

1.0 g m

of magnesium pyrophosphate

({M g}_{2} P_{2} O_{7})

. The percentage of phosphorous in the organic compound is:

0.5

g of an organic substance containing phosphorous was heated with conc.

H N O_{3}

in the Carius tube. The phosphoric acid thus formed was precipitated with magnesia mixture,

(M g N H_{4} P O_{4})

, which on ignition gave a residue of

1.0

g of magnesium pyrrophosphate

(M g_{2} P_{2} O_{7})

. The percentage of phosphorous in the organic compound is :

0.5

g of an organic substance containing phosphorus was heated with conc.

H N O_{3}

in the carius tube. The phosphoric acid thus, formed was precipitated with magnesia mixture,

(M g N H_{4} P O_{4})

which on ignition gave a residue of

1.0

g of magnesium pyrophosphate,

(M g_{2} P_{2} O_{7})

. The percentage of phosphorous in the organic compound is:

0.4037

g of an organic compound containing

S

was treated with conc.

H N O_{3}

in a Carius tube. On precipitation with

B a C l_{2}

0.1936

g of

B a S O_{4}

was

0.35

g. Find the percentage of sulphur.

Join BYJU'S Learning Program

0.248 g of an organic compound was heated in carious tube with conc. HNO3. Produced H3PO4 was precipitated as Mg(NH4)PO4, which formed 0.444 g Mg2P2O7 on ignition. What percentage of ′P′ is present in compound? (Mg=24,P=31)

The correct option is B 50%Moles of Mg2P2O7=0.444222=2×10−3 molesMass of P in Mg2P2O7=2×10−3×62=124×10−3%Pinorganiccompound=MassofPMassoforganiccompound×100=124×10−30.248×100=50%

0.248 g of an organic compound was heated in carious tube with conc. ${H N O}_{3}$ . Produced $H_{3} {P O}_{4}$ was precipitated as $M g ({N H}_{4}) {P O}_{4}$ , which formed 0.444 g ${M g}_{2} P_{2} O_{7}$ on ignition. What percentage of $^{'} P^{'}$ is present in compound?
$(M g = 24, P = 31)$