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Atomic Number and Mass Number

0.25 g of an ...

Question

$0.25 g$ of an element $M$ reacts with excess fluorine to produce $0.547 g$ of the hexafluoride $M F_{6}$ . What is the element?

C r

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M o

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S

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T e

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Solution

The correct option is A $M o$
We have

$M + F_{2} \to M F_{6}$

moles of M = moles of $M F_{6}$

let mass of element M = $x g$

therefore we have

$\frac{0.25}{x} = \frac{0.547}{x + 114}$

so, solving we get , $x = 95.9 g$

therefore, the elemnt is $M o$

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