Question

$0.2595$ g of an organic substance, when treated by carius method, gave $0.25$ g of $BaS{O}_4$. Calculate the percentage of sulphur in the compound.

• A. $9.08$%
• B. $12.75$%
• C. $15.96$%
• D. $13.23$%

Answer 1

The correct option is D $13.23$%

$\%$ of Sulphur $=\frac{32}{233}\times \frac{MassofBaS{O}_{4}formed}{Massoforganiccompound}\times 100$

$⟹\%$ of Sulphur $=\frac{32}{233}\times \frac{0.25}{0.2595}\times 100$

$⟹\%$ of Sulphur $=13.23\%$ (approx.)

Option D is correct.