$0.284$ g of an organic substance gave $0.287$ g of silver chloride in a Carius estimation of halogen. Find out the percentage of chlorine in the compound.
$(A g = 108, C l = 35.5)$

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Solution

The correct option is B $25$ %
According to Carius determination method,
$%$ of $C l = \frac{35.5}{108 + 35 + 5} \times \frac{M a s s o f A g C l}{M a s s o f o r g a n i c c o m p o u n d} \times 100$
$⟹ %$ of $C l = 0.247 \times \frac{0.287}{0.284} \times 100$
$⟹ %$ of $C l = 25 %$ (approx)

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0.284 g of an organic substance gave 0.287 g of silver chloride in a Carius estimation of halogen. Find out the percentage of chlorine in the compound.(Ag=108,Cl=35.5)

The correct option is B 25%According to Carius determination method,% of Cl=35.5108+35+5×MassofAgClMassoforganiccompound×100⟹% of Cl=0.247×0.2870.284×100⟹% of Cl=25% (approx)

$0.284$ g of an organic substance gave $0.287$ g of silver chloride in a Carius estimation of halogen. Find out the percentage of chlorine in the compound.
$(A g = 108, C l = 35.5)$

The correct option is B $25$ %
According to Carius determination method,
$%$ of $C l = \frac{35.5}{108 + 35 + 5} \times \frac{M a s s o f A g C l}{M a s s o f o r g a n i c c o m p o u n d} \times 100$
$⟹ %$ of $C l = 0.247 \times \frac{0.287}{0.284} \times 100$
$⟹ %$ of $C l = 25 %$ (approx)