Question

0.2g atoms of silicon combine with 21.36 g of chlorine.

Find the empirical formula of the compound formed.

Answer 1

element	given weight	atomic weight	moles	simple whole no.ratio
Si	5.76g	28g	0.2	1
Cl	21.36g	35.5g	0.6	3

Step1:- divided both
element their atomic
weight

si :- given 0.2 g atom it
mean this is mole of Si
mole =weight/molecular weight

0.2=weight/28.8

weight=5.76g
now

Si :- 5.76/28.8=0.2

Cl:- 21.3g/35.5g=213/355=0.6

step2:-now take of
both element
Si:Cl=0.2:0.6=1:3

now we look here one
part of silicon react
with 3 part of chlorine
so, empirical
formula=$SiC{l}_3$