0.2g of organic compound on complete combustion produces 0.18 g of water, the % of hydrogen in it is

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Solution

The correct option is B 10
$% o f H = \frac{2 \times mass of water \times 100}{18 \times mass of compound} = \frac{2 \times 0.18 \times 100}{18 \times 0.2} = 10$

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0.2g of organic compound on complete combustion produces 0.18 g of water, the % of hydrogen in it is

The correct option is B 10% of H=2×mass of water×10018×mass of compound=2×0.18×10018×0.2=10

The correct option is B 10
$% o f H = \frac{2 \times mass of water \times 100}{18 \times mass of compound} = \frac{2 \times 0.18 \times 100}{18 \times 0.2} = 10$