(0, -3) and (4, 0) are solutions of the linear equation:

3x - 4y = 12

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4x + 3y = 12

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3x + 4y = 1

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4x - 3y = 12

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Solution

The correct option is A
3x - 4y = 12

(i) Put (0, -3) in 3x + 4y = 12

LHS

= 3(0) + 4(-3)

= -12 RHS

(ii) Put (0, -3) in 4x - 3y = 12

LHS

= 4(0) - 3(-3)

= 9 RHS

(iii) Put (0, -3) in 4x + 3y = 12

LHS

= 4(0) + 3(-3)

= -9 RHS

(iv) Put (0, -3) in 3x - 4y = 12

LHS

= 3(0) - 4(-3)

= 12 = RHS

Put (4, 0) in 3x - 4y =12

LHS

= 3(4) - 4(0)

= 12 = RHS

Hence, 3x - 4y = 12 has (0, -3) and (4, 0) as solutions.

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