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Stoichiometry

0.3 g of an a...

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0.3 g of an acid is neutralised by 40 cm3 of 0.125 N NaOH. Equivalent mass of the acid is

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Q. 0.5 g of an acid is neutralized by 40 cc of 0.125 N

N a O H

. The equivalent mass of the acid is

0.14

g of an acid required

12.5

0.1

N a O H

for complete neutralisation. The equivalent mass of the acid is :

0.25 g

of an acid can exactly neutralise

20 m l

0.125 N

base. Equivalent weight of the acid is:

Q. Volume of 0.1 M NaOH required to completely neutralise

40 c m^{3}

of 0.1 M oxalic acid is

a .

Define the term neutralisation equivalent of an acid.

b .

Find the number of ionisable

H

atoms for a polycarboxyclic acid

(M w = 210 g m m o l^{- 1})

with a neutralisation equivalent of

70 g m e q^{- 1}

. How many equivalents of

N a O H

would be neutralized by

1 m o l

c .

Find the neutralisation equivalent of mellitic acid,

C_{6} (C O O H)_{6}

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