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Standard IX
Chemistry
Molecular Mass
0.32 g of a m...
Question
0.32
g of a metal gave on treatment with an acid
112
mL of hydrogen at NTP. Calculate the equivalent mass of the metal.
A
58
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B
32
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C
64
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D
24
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Solution
The correct option is
B
32
Eq. wt of metal
=
wt of metal
×
11200
V of
H
2
in ml displaced at STP
=
0.32
×
11200
112
=
32
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