0-35 g of an organic compound was Kjeldahlised and ammonia evolved was absorbed in 100 mL of N5 H2SO4 the residual acid required 154 mL of N10 NaOH for neutralisation- Calculate the percentage of nitrogen in the compound-

By using formula Percentage of nitrogen = nbsp;1.4 × N × VWt. of substance Where N V = M_eq of acid neutralised by ammonia Total M_eq of acid taken = N× V = ...

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Byju's Answer

Standard XII

Chemistry

Organic Compounds

0.35 g of an ...

Question

$0.35 g$ of an organic compound was Kjeldahlised and ammonia evolved was absorbed in $100 mL$ of $\frac{N}{5} H_{2} S O_{4}$ the residual acid required $154 mL$ of $\frac{N}{10} N a O H$ for neutralisation. Calculate the percentage of nitrogen in the compound.

18.4 %

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81.6 %

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62.4 %

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37.6 %

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Solution

The correct option is A $18.4 %$
By using formula
$Percentage of nitrogen = \frac{1.4 \times N \times V}{Wt. of substance}$
$Where N V = M_{e q} of acid neutralised by ammonia$
$Total M_{e q} of acid taken = N \times V = \frac{1}{5} \times 100 = 20$
$M_{e q} of NaOH used to neutralise acid = \frac{1}{10} \times 154 = 15.4$
$M_{e q} of acid neutralised by ammonia = 20.0 - 15.4 = 4.6$
$Percentage of nitrogen = \frac{1.4 \times 4.6}{0.35} = 18.4 %$

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0.35 g of an organic compound was Kjeldahlised and ammonia evolved was absorbed in 100 mL of N5H2SO4 the residual acid required 154 mL of N10NaOH for neutralisation. Calculate the percentage of nitrogen in the compound.

$0.35 g$ of an organic compound was Kjeldahlised and ammonia evolved was absorbed in $100 mL$ of $\frac{N}{5} H_{2} S O_{4}$ the residual acid required $154 mL$ of $\frac{N}{10} N a O H$ for neutralisation. Calculate the percentage of nitrogen in the compound.