Question

0.36 g of $Mg$ combines with chlorine to produce 1.425 g of magnesium chloride. 9.50 g of another sample of anhydrous magnesium chloride gave, on electrolysis 2.24 litre of chlorine at NTP. Show that these data agree with the law of constant proportions.

Answer 1

$0.36g$ of $Mg$ gives $1.425g$ of $MgC{l}_2$ with $C{l}_2$.

The mass of $C{l}_2$ reacted $=1.425-0.36=1.065g$

$\therefore 1g$ of $MgC{l}_2$ has $=\frac{1.065}{1.425}=0747g$ of $C{l}_2.⟶1$

$9.5g$ of $MgC{l}_2$ gives $\frac{2.24}{9.5}=0.235L$ of $C{l}_2.$

$70.9g$ occupies $22.4d{m}^3$ volume.

$\therefore 0.235d{m}^3$ of volume contains $=\frac{0.235\times 70.9}{22.4}=0.743g$ of $C{l}_2.⟶2$

From $1$ and $2$, it illustrates the law of constant proportions.