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Energy Levels

0.38ev n 6 ...

Question

$0.38 e v$ ___ $n 6$
$0.54 e v$ _ $n 5$
$0.85 e v$ _ $n 4$
$1.52 e v$ _ $n 3$
$3.39 e v$ _ $n 2$
$13.6 e v$ ___ $n 1$
A hydrogen electron falls from the $n = 3$ to the $n = 1$ energy level. Using the chart above, determine how much energy it must release:

A

+ 0.97 e V

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B

+ 2.85 e V

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C

+ 10.29 e V

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D

+ 12.08 e V

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E

+ 13.06 e V

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Solution

The correct option is D $+ 12.08 e V$
The energy released will be given by:
$Δ E = E_{3} - E_{1}$
$Δ E = - 1.52 - (- 13.6)$
$Δ E = + 12.08 e V$

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Similar questions

Q. This question relates to the electron energy level diagram below. The questions are about a hydrogen electron located at

E_{3}

0.38 e v

n = 6

-

0.54 e v

n = 5

-

0.85 e v

n = 4

-

1.52 e v

n = 3

-

3.39 e v

n = 2

-

13.6 e v

n = 1

what is the emission energy when it moves to

E_{5}

?

Q. The following question relates to the partial energy level diagram for the hydrogen electron:

.54 e V

n_{5}

.85 e V

n_{4}

1.51 e V

n_{3}

3.4 e V

n_{2}

13.6 e V

n_{1}

The question relates to a hydrogen electron located at

E_{3}

.What is the emission energy when the electron falls to

E_{5}

E_{3}

?

Q. Solve the following question which relates to the partial energy level diagram for the hydrogen electron:

.54 e V

n_{5}

.85 e V

n_{4}

1.51 e V

n_{3}

3.4 e V

n_{2}

13.6 e V

n_{1}

The question relates to a hydrogen electron located at

E_{3}

. What is the emission energy when the electron falls to

E_{2}

E_{3}

?

n_{1} < n_{2} < n_{3} < n_{4} < n_{5}

be positive such that

n_{1} + n_{2} + n_{3} + n_{4} + n_{5} = 20

. The numbers of such distinct arrangements

(n_{1}, n_{2}, n_{3}, n_{4}, n_{5})

n_{1} < n_{2} < n_{3} < n_{4} < n_{5}

be positive integers such that

n_{1} + n_{2} + n_{3} + n_{4} + n_{5} = 20.

The number of such distinct arrangements

(n_{1}, n_{2}, n_{3}, n_{4}, n_{5})

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