Question

0.41 g of an organic compound gave on combustion 0.8010 g of CO2 and 0.4212 g of H2O.Calculate the % composition of carbon & hydrogen in it.

Answer 1

$$\begin{gathered} \%ofC=\frac{12}{44}\times \frac{WeightofC{O}_2}{Weightoforganiccompound}\times 100 \\ =\frac{12}{44}\times \frac{0.8010}{0.41}\times 100 \\ =53.28\% \\ \%ofH=\frac{2}{18}\times \frac{Weightof{H}_{2}O}{Weightoforganiccompound}\times 100 \\ =\frac{2}{18}\times \frac{0.4212}{0.41}\times 100 \\ =11.41\% \end{gathered}$$