Question

0.46 g of an organic compound was analysed. The increase in mass of $CaC{l}_2$ U-Tube was 0.54 g and potash bulb was 0.88 g. The percentage composition of the compound is:

• A. C=52.17%, H=13.04%, O=34.79%
• B. C=50%,H=50%
• C. C=32.19%,H= 18.01%,O=49.8%
• D. C=72%,H=28%

Answer 1

The correct option is A C=52.17%, H=13.04%, O=34.79%

Weight of organic compound = 0.46g

Weight of $H_{2}O$ = 0.54g

Weight of $C{O}_2$ = 0.88g

$\%\text{of H/}{H}_{2}O=\frac{2}{18}\times \frac{0.54}{0.46}\times 100=13.04\%$

$\%\text{ofC/}C{O}_2=\frac{12}{44}\times \frac{0.88}{0.46}\times 100=52.17\%$

$\%\text{of O}=100-(\%\text{of C}+\%\text{of H})=100-(52.17+13.04)=34.79\%$