Question

$0.49\text{g}$ of an acid (molar mass: $90\text{g/mol}$) was neutralized by $20\text{mL}$ of $0.54\text{N}$ caustic potash. The basicity of the acid is:

• A. 1
• B. 3
• C. 2
• D. 4

Answer 1

The correct option is C 2

Let the basicity (n-factor) of the acid be $x$.
Equivalents of the acid = equivalents of $KOH$
$x\times \frac{0.49}{90}=\frac{0.54}{1000}\times 20$
On solving for $x$, Basicity $=1.98\sim 2$