Question

0.5 F of electricity is passed through 500 mL of copper sulphate solution. The amount of copper which can be deposited will be:

• A. $63.5g$
• B. $31.75g$
• C. $15.8g$
• D. Unpredictable

Answer 1

The correct option is C $15.8g$

$C{u}^{2+}+2e^{-}\to Cu$

$\therefore 2F=1molofCu=63.5gofCu$

$⟶0.5F$ = $\frac{63.5}{2}\times 0.5=15.8g$

Hence, option C is correct.