Question
0.5H2(g)+0.5Cl2(g)→HCl(g); ΔH0298= −22060 cal
The mean heat capacities over this temperature range are,
H2(g), Cp=6.82 calmol−1K−1; Cl2(g), Cp=7.7 calmol−1K−1; HCl(g), Cp=6.81 calmol−1K−1
The magnitude of the heat of formation of HCl(g)(in cal) at 348 K from the above data will be: