0-5 kg of water is heated from 20- C to 70- C- If the specific heat of water is 4200 J - kg - K- determine the change in internal energy of water-A- 105 kJB - 85 kJC- 95 kJD- 65 kJ

The correct option is A 105 kJGiven: Mass of water, m = 0.5 kg, Specific heat of water, S = 4200 J/kgK Initial temperature, T_1 = 20 ^∘ C Final temperature, T_ ...

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Byju's Answer

Standard VIII

Physics

Heat Capacity

0.5 kg of wat...

Question

$0.5 k g$ of water is heated from $20^{\circ} C$ to $70^{\circ} C$ . If the specific heat of water is $4200 \frac{J}{k g . K}$ , determine the change in internal energy of water.

105 k J

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85 k J

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95 k J

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65 k J

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Solution

The correct option is A $105 k J$
Given:
Mass of water, $m = 0.5 k g$ ,
Specific heat of water, $S = 4200 \frac{J}{k g K}$
Initial temperature, $T_{1} = 20^{\circ} C$
Final temperature, $T_{2} = 70^{\circ} C$

Hence, temperature change,
$Δ T = T_{2} - T_{1}$
$Δ T = 50^{\circ} C$

Since, amount of heat absorbed by a substance,
$Q = m S Δ T$
$Q = 0.5 \times 4200 \times 50$
$Q = 105, 000 J = 105 k J$

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0.5 kg of water is heated from 20 ∘C to 70 ∘C. If the specific heat of water is 4200 Jkg.K, determine the change in internal energy of water.

$0.5 k g$ of water is heated from $20^{\circ} C$ to $70^{\circ} C$ . If the specific heat of water is $4200 \frac{J}{k g . K}$ , determine the change in internal energy of water.