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Chlorination

0.5 L of gase...

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0.5 L of gaseous hydrocarbon when burnt in excess of O_2 gave 3.5 L of CO_2 and 4L of water vapours under same conditions. Molecular formula of the hydrocarbon will be 1)C_4H_8 2)C_4H_{10} 3)C_7H_{16} 4)C_5H_1

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500 m L

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