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Types of Redox Reactions

0.5 M HCl ...

Question

$0.5 M$ $H C l$ $(25 m L)$ $+ 0.5 M$ $N a O H$ $(10 m L)$ $+ 40 m L H_{2} O$
Find the pH of the resulting solution.

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Solution

The correct option is C $1$
We first find the resulting molarity of the solution.
For an acid-base mixture, resulting molarity is given as:
$M = \frac{M_{1} V_{1} - M_{2} V_{2}}{V} = \frac{(0.5 \times 25) - (0.5 \times 10)}{75} = 0.1 M$
$[H^{+}]$ $= n \times α \times C =$ $1 \times 1 \times 0.1$ $=$ $0.1 m o l / d m^{3}$ , where n=1
$p H$ $=$ $- l o g_{10} [H^{+}]$ = $- l o g_{10} 0.1$ $=$ $1$

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