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Question

0.5 ml of H2 and 0.5 mole of I2 react in 10 litre flask at 448oC. The equilibrium constant Kc is 50 for H2(g)+I2(g)2HI(g)
What is the value of Kp?

A
50
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B
20
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C
10
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D
40
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Solution

The correct option is A 50
The given reaction is :-
H2(g)+I2(g)2HI(g)
we have, KP=KC(RT)n
n= No. of moles of gaseous (product - reactant)
=211=0
KP=KC(RT)0KP=KC=50.

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