0.5mol of each of H2,SO2andCH4 are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be:
A
pH2>pSO2>pCH4
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B
pH2>pCH4>pSO2
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C
pSO2>pH2>pCH4
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D
pSO2>pCH4>pH2
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Solution
The correct option is DpSO2>pCH4>pH2 Rate of diffusion∝1√Molecular mass
Order of diffusion: H2>CH4>SO2
and amount left is in the order, SO2>CH4>H2
Hence, order of partial pressure is, pSO2>pCH4>pH2