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Byju's Answer
Standard XII
Chemistry
Characteristics of Equilibrium Constant
0.5 mol of ...
Question
0.5
m
o
l
of
H
2
and
0.5
m
o
l
e
of
I
2
react in
10
litre flask at
448
o
C
. the equilibrium constant
K
c
is
50
for
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
.
What is the value of
K
p
?
Open in App
Solution
H
2
+
I
2
⇌
2
H
I
Δ
n
=
0
K
P
=
K
C
(
R
T
)
Δ
n
=
50
(
8.314
×
721
)
0
=
50
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0
Similar questions
Q.
0.5
ml of
H
2
and
0.5
mole of
I
2
react in
10
litre flask at
448
o
C. The equilibrium constant
K
c
is
50
for
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
What is the value of
K
p
?
Q.
In a
7.0
L
evacuated chamber,
0.50
m
o
l
H
2
and
0.50
m
o
l
I
2
react at
427
o
C
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
. At the given temperature,
K
c
=
49
for the reaction
What is the value of
K
p
?
Q.
In the reaction,
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
, in a
2
litre flask
0.4
mole of each
H
2
and
I
2
are taken. At equilibrium
0.5
mol of
H
I
are formed. What will be the value of equilibrium constant
K
c
?
Q.
For the reaction
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
,
If
0.5
mole
H
2
is reacted with
0.5
mole
I
2
in a ten-litre container at
444
o
C
and at same temperature value of equilibrium constant
K
c
is
49
, the ratio for
[
H
I
]
and
[
I
2
]
will be:
Q.
At
700
K
, equilibrium constant for the reaction:
H
2
(
g
)
+
I
2
(
g
)
⇌
2
H
I
(
g
)
is
64
. If
0.5
m
o
l
L
−
1
of
H
I
(
g
)
is present at equilibrium at
700
K
, what are the concentration of
H
2
(
g
)
and
I
2
(
g
)
assuming that we initially started with
H
I
(
g
)
and allowed it to reach equilibrium at
700
K
?
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