0.5 mole each of two ideal gases A (Cv,m=52R) and B (Cv,m=3R) are taken in a container and expanded reversibly and adiabatically. During this process, temperature of gaseous mixture decreased from 350 K and 250 K. Then, for the process :
A
ΔU=−100R
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B
ΔU=−275R
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C
ΔH=−375R
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D
ΔH=−300R
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Solution
The correct option is CΔU=−275R ΔU=nCAv,mΔT+nCBv,mΔT=−0.5×5/2R×100−0.5×3R×100